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Java Program to get the content of a directory
The contents of a directory can be obtained using the method java.io.File.listFiles(). This method requires no parameters and it returns the abstract path names that specify the files and directories in the required directory.
A program that demonstrates this is given as follows −
Example
import java.io.File;
public class Demo {
public static void main(String[] args) {
File directory = new File("C:\JavaProgram");
File[] contents = directory.listFiles();
for (File c : contents) {
if(c.isFile())
System.out.println(c + " is a file");
else if(c.isDirectory())
System.out.println(c + " is a directory");
}
}
}The output of the above program is as follows −
Output
C:\JavaProgram\D is a directory C:\JavaProgram\Demo.class is a file C:\JavaProgram\Demo.java is a file C:\JavaProgram\Demo.txt is a file
Now let us understand the above program.
The method java.io.File.listFiles() is used to obtain the contents of the directory "C:\JavaProgram". Then these path names are displayed using the methods java.io.File.isFile() and java.io.File.isDirectory() that specify whether they are files or directories. A code snippet that demonstrates this is given as follows −
File directory = new File("C:\JavaProgram");
File[] contents = directory.listFiles();
for (File c : contents) {
if(c.isFile())
System.out.println(c + " is a file");
else if(c.isDirectory())
System.out.println(c + " is a directory");
}
Updated on: 30-Jul-2019
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