Java Program to cube sum of first n natural numbers

JavaObject Oriented ProgrammingProgramming

Following is the Java code to cube sum of first n natural numbers −

Example

 Live Demo

import java.util.*;
import java.lang.*;
public class Demo{
   public static int first_n_nat_no(int val){
      int ini_sum = 0;
      for (int x=1; x<=val; x++)
      ini_sum += x*x*x;
      return ini_sum;
   }
   public static void main(String[] args){
      int val = 7;
      System.out.println("The sum of cube of first 7 natural numbers is ");
      System.out.println(first_n_nat_no(val));
   }
}

Output

The sum of cube of first 7 natural numbers is
784

A class named Demo defines a static function that takes a value as parameter. Here, an initial sum is defined as 0. Next, a ‘for’ loop is run over values 1 to the value passed as parameter. This is the value up to which the cubes of numbers beginning from 1 need to be computed. Next, every element up to the value is multiplied with itself thrice and returned. Next, the main function defines the value up to which the cube of numbers need to be found. It is calculated and displayed on the console.

raja
Published on 04-Jul-2020 09:54:45
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