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Is it possible to get list of defined namespaces in PHP
Given file 1 has namespace ns_1 and file 2 has namespace ns_2, if file 1 and file 2 are included in file 3, there is no way to know that namespaces ns_1 and ns_2 have been loaded.
The only way is to use the ‘class_exists’ function and the list of classes with the specific namespace can be obtained using ‘get_declared_classes’. Simply put, this data obtained can be used to find a matching namespace given all the declared class names −
function namespaceExists($namespace) {
$namespace .= "\";
foreach(get_declared_classes() as $name)
if(strpos($name, $namespace) === 0) return true;
return false;
}----Or---
Example
<?php
namespace FirstNamespace;
class new_class {}
namespace SecondNamespace;
class new_class {}
namespace ThirdNamespace\FirstSubNamespace;
class new_class {}
namespace ThirdNamespace\SecondSubNamespace;
class new_class {}
namespace SecondNamespace\FirstSubNamespace;
class new_class {}
$namespaces=array();
foreach(get_declared_classes() as $name) {
if(preg_match_all("@[^\\]+(?=\\)@iU", $name, $matches)) {
$matches = $matches[0];
$parent =&$namespaces;
while(count($matches)) {
$match = array_shift($matches);
if(!isset($parent[$match]) && count($matches))
$parent[$match] = array();
$parent =&$parent[$match];
}
}
}
print_r($namespaces);Output
This will produce the following output −
Array ( [FirstNamespace] => [SecondNamespace] => Array ( [FirstSubNamespace] => ) [ThirdNamespace] => Array ( [FirstSubNamespace] => [SecondSubNamespace] => ) )
Different namespaces are created (FirstNamespace, SecondNamespace..) and empty class is declared (new_class). An array of namespaces is created and a foreach loop runs through the classes that are declared. A regular expression match is done and the namespaces that are defined in that specific environment will be displayed.
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