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Is it possible to combine 'DISTINCT' and 'COUNT' queries, so that I can see how many times each distinct value appears in a MySQL table column?
Yes, you can use aggregate function COUNT(*) along with GROUP BY clause. Let us first create a −
mysql> create table DemoTable1425 -> ( -> JoiningYear int -> ); Query OK, 0 rows affected (0.76 sec)
Insert some records in the table using insert −
mysql> insert into DemoTable1425 values(2000); Query OK, 1 row affected (0.15 sec) mysql> insert into DemoTable1425 values(2010); Query OK, 1 row affected (0.24 sec) mysql> insert into DemoTable1425 values(2015); Query OK, 1 row affected (0.12 sec) mysql> insert into DemoTable1425 values(2000); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable1425 values(2010); Query OK, 1 row affected (0.14 sec) mysql> insert into DemoTable1425 values(2000); Query OK, 1 row affected (0.11 sec) mysql> insert into DemoTable1425 values(2010); Query OK, 1 row affected (0.10 sec)
Display all records from the table using select −
mysql> select * from DemoTable1425;
This will produce the following output −
+-------------+ | JoiningYear | +-------------+ | 2000 | | 2010 | | 2015 | | 2000 | | 2010 | | 2000 | | 2010 | +-------------+ 7 rows in set (0.00 sec)
Following is the query to see how many times each distinct value appears −
mysql> select JoiningYear,count(*) from DemoTable1425 group by JoiningYear;
This will produce the following output −
+-------------+----------+ | JoiningYear | count(*) | +-------------+----------+ | 2000 | 3 | | 2010 | 3 | | 2015 | 1 | +-------------+----------+ 3 rows in set (0.00
Updated on: 12-Nov-2019
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