Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
Invalid Transactions in C++
Suppose there are some transactions. A transaction is possibly invalid if −
The amount exceeds $1000, or;
If it occurs within (and including) 60 minutes of another transaction with the same name in a different city.
Here each transaction string transactions[i] consists of comma separated values representing the name, time (in minutes), amount, and city of the transaction. We have a list of transactions, find a list of transactions that are possibly invalid. So if the input is like ["alice,20,800,mtv", "bob,50,1200,mtv"], then the answer will be ["bob,50,1200,mtv"].
To solve this, we will follow these steps −
Define a set s. Define a map m
for i in range 0 to size of t – 1
x := t[i]
temp := node using string x
for j in range 0 to size of m[name of temp]
y := m[name of temp][j]
if city of y is not city of temp and |time of y – time of temp| −= 60
insert node y into set s as string, and insert x into s
if the amount of temp > 1000, then insert x into s
insert temp into m[name of temp]
return the items in the set s
Example(C++)
Let us see the following implementation to get a better understanding −
#include <bits/stdc++.h>
using namespace std;
void print_vector(vector<auto> v){
cout << "[";
for(int i = 0; i<v.size(); i++){
cout << v[i] << ", ";
}
cout << "]"<<endl;
}
class Node{
public:
string name;
string city;
int time;
int amount;
};
class Solution {
public:
Node getNode(string s){
string temp = "";
Node ret;
int cnt = 0;
for(int i = 0; i < s.size(); i++){
if(s[i] == ','){
if(cnt == 0){
ret.name = temp;
}
else if(cnt == 1){
ret.time = stoi(temp);
}
else if(cnt == 2){
ret.amount = stoi(temp);
} else {
ret.city = temp;
}
cnt++;
temp = "";
continue;
}
temp += s[i];
}
ret.city = temp;
return ret;
}
vector<string> invalidTransactions(vector<string>& t) {
set <string >s;
map <string ,vector < Node >> m;
for(int i = 0; i < t.size(); i++){
string x = t[i];
Node temp = getNode(x);
for(int j = 0; j < m[temp.name].size(); j++){
Node y = m[temp.name][j];
if(y.city != temp.city && abs(y.time - temp.time) <= 60){
s.insert(y.name + "," + to_string(y.time) + "," + to_string(y.amount) + "," + y.city);
s.insert(x);
}
}
if(temp.amount > 1000){
s.insert(x);
}
m[temp.name].push_back(temp);
}
vector <string> ret(s.begin(), s.end());
return ret;
}
};
main(){
vector<string> v1 = {"alice,20,800,mtv","bob,50,1200,mtv"};
Solution ob;
print_vector(ob.invalidTransactions(v1));
}Input
["alice,20,800,mtv","bob,50,1200,mtv"]
Output
[bob,50,1200,mtv, ]
140 Views
