Insertion Sort List in C++

Suppose we have a linked list, we have to perform the insertion sort on this list. So if the list is like [9,45,23,71,80,55], sorted list is [9,23,45,55,71,80].

To solve this, we will follow these steps −

• dummy := new Node with some random value
• node := given list
• while node is not null,
  • newNode = next of node, dummyHead := next of dummy, prevDummyHead := dummy
  • while true −
    • if dummyHead is not present, value of dummyHead > value of node
      • next of node := dummyHead
      • next of prevDummyHead := node
      • break the loop
    • prevDummyHead := dymmyHead, and dummyHead = next of dummy head
  • node := nextNode
• return next of dummy

Let us see the following implementation to get better understanding −

Example

 Live Demo

#include <bits/stdc++.h>
using namespace std;
class ListNode{
   public:
      int val;
      ListNode *next;
      ListNode(int data){
         val = data;
         next = NULL;
      }
};
ListNode *make_list(vector<int> v){
   ListNode *head = new ListNode(v[0]);
   for(int i = 1; i<v.size(); i++){
      ListNode *ptr = head;
      while(ptr->next != NULL){
         ptr = ptr->next;
      }
      ptr->next = new ListNode(v[i]);
   }
   return head;
}
void print_list(ListNode *head){
   ListNode *ptr = head;
   cout << "[";
   while(ptr){
      cout << ptr->val << ", ";
      ptr = ptr->next;
   }
   cout << "]" << endl;
}
class Solution {
   public:
   ListNode* insertionSortList(ListNode* a) {
      ListNode* dummy = new ListNode(-1);
      ListNode* node = a;
      ListNode* nextNode;
      ListNode* dummyHead;
      ListNode* prevDummyHead;
      while(node != NULL){
         nextNode = node->next;
         dummyHead = dummy->next;
         prevDummyHead = dummy;
         while(1){
            if(!dummyHead || dummyHead->val > node->val){
               node->next = dummyHead;
               prevDummyHead->next = node;
               //cout << prevDummyHead->val << " " << node->val << endl;
               break;
            }
            prevDummyHead = dummyHead;
            dummyHead = dummyHead->next;
         }
         node = nextNode;
      }
      return dummy->next;
   }
};
main(){
   vector<int> v = {5,3,2,0,-4,7};
   ListNode *head = make_list(v);
   Solution ob;
   print_list(ob.insertionSortList(head));
}

Input

{5,3,2,0,-4,7}

Output

[-4, 0, 2, 3, 5, 7, ]

Arnab Chakraborty

Updated on: 04-May-2020

161 Views

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