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Implementing incremental search and display the values with a specific number in MySQL?
For this, you can use SUBSTRING_INDEX(). Let us first create a table −
mysql> create table DemoTable (Number varchar(100)); Query OK, 0 rows affected (0.60 sec)
Example
Insert some records in the table using insert command −
mysql> insert into DemoTable values('235678');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable values('1634990');
Query OK, 1 row affected (0.23 sec)
mysql> insert into DemoTable values('678590');
Query OK, 1 row affected (0.46 sec)
mysql> insert into DemoTable values('908765432');
Query OK, 1 row affected (0.14 sec)
mysql> insert into DemoTable values('222343388773');
Query OK, 1 row affected (0.35 sec)
mysql> insert into DemoTable values('09028215');
Query OK, 1 row affected (0.51 sec)Display all records from the table using select statement −
mysql> select *from DemoTable;
Output
+--------------+ | Number | +--------------+ | 235678 | | 1634990 | | 678590 | | 908765432 | | 222343388773 | | 09028215 | +--------------+ 6 rows in set (0.00 sec)
Following is the query to get values with a particular number in MySQL −
mysql> select Number from DemoTable where Number LIKE '%5%' ORDER BY LENGTH(SUBSTRING_INDEX(Number, '5', 1));
Output
+-----------+ | Number | +-----------+ | 235678 | | 678590 | | 908765432 | | 09028215 | +-----------+ 4 rows in set (0.00 sec)
Updated on: 02-Jul-2020
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