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Implement Rand10() Using Rand7() in C++
Suppose we have a function rand7 which generates a uniform random integer in the range 1 to 7, we have to write another function rand10 which generates a uniform random integer in the range 1 to 10. We cannot use some library function to generate random numbers.
Suppose we want two random numbers, so they may be [8,10].
To solve this, we will follow these steps −
- rand40 := 40
- while rand40 >= 40
- rand40 := (rand7() - 1) * 7 + (rand7() – 1)
- return rand40 mod 10 + 1
Let us see the following implementation to get better understanding −
Example
#include <bits/stdc++.h>
using namespace std;
int rand7(){
return 1 + rand() % 7;
}
class Solution {
public:
int rand10() {
int rand40 = 40;
while(rand40 >= 40){
rand40 = (rand7() - 1) * 7 + (rand7() - 1);
}
return rand40 % 10 + 1;
}
};
main(){
srand(time(NULL));
Solution ob;
cout << (ob.rand10()) << endl;
cout << (ob.rand10()) << endl;
cout << (ob.rand10()) << endl;
}Input
Call the function three times
Output
2 2 6
Updated on: 02-May-2020
269 Views
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