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HTML DOM WheelEvent deltaX Property
The HTML DOM WheelEvent deltaX property returns a signed number corresponding to whether user is scrolling left or right, if user is scrolling in any other direction this property returns 0.
Syntax
Following is the syntax −
Returning signed number
event.deltaX
Let us see an example of HTML DOM WheelEvent deltaX property −
Example
<!DOCTYPE html>
<html>
<head>
<title>HTML DOM WheelEvent deltaX</title>
<style>
* {
padding: 2px;
margin:5px;
}
form {
width:70%;
margin: 0 auto;
text-align: center;
}
input[type="button"] {
border-radius: 10px;
}
#content {
width: 80px;
height: 80px;
margin: 20px 0 0 50px;
background-color: #dc3545;
transition: all 2s ease-in-out;
}
</style>
</head>
<body>
<form>
<fieldset>
<legend>HTML-DOM-WheelEvent-deltaX</legend>
<div id="content" onwheel="setControls(event)"></div>
<input type="button" value="reset" onclick="resetCSS()">
<div id="divDisplay">Scroll over div element</div>
</fieldset>
</form>
<script>
var playDiv = document.getElementById("content");
var count = 40;
function setControls(event) {
var valX = event.deltaX;
var valY = event.deltaY;
if(valY>0){
playDiv.style.transform = "scale(0.5)";
playDiv.style.backgroundColor = "rgba(0, 188, 212, 0.47)";
playDiv.style.borderRadius = "50%";
}
else if(valY<0){
playDiv.style.transform = "scale(1.5)";
playDiv.style.backgroundColor = "rgba(0, 188, 0, 0.47)";
playDiv.style.borderRadius = "0px";
}
else if(valX>0){
count+=40;
playDiv.style.transform = "translateX("+count+"px)";
}
else{
count-=40;
playDiv.style.transform = "translateX("+count+"px)";
}
}
function resetCSS(){
count = 40;
var st = "width: 80px;height: 80px;margin: 20px 0 0 50px;background-color:
#dc3545;transition: all 2s ease-in-out;";
playDiv.style = st;
}
</script>
</body>
</html>Output
Scrolling over div element in left direction −
Scrolling over div element in right direction −
Clicking reset button −
Updated on: 21-Dec-2021
101 Views
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