How will you find the ORDER_ID of all the orders having ORDER_TOTAL greater than the average of ORDER_TOTAL in ORDER's DB2 table

We can find all the ORDER_ID which are having ORDER_TOTAL greater than the average value of all the ORDER_TOTAL present in the ORDERS table using the sub-query.

For example, if we have below ORDERS table.

Below is the subquery to find out the desired data.

Example

SELECT ORDER_ID, ORDER_TOTAL FROM ORDERS
   WHERE ORDER_TOTAL > (SELECT AVG(ORDER_TOTAL) FROM ORDERS)

The result of the above query will be as below.

Mandalika

Published on 30-Nov-2020 09:32:16

• Related Questions & Answers
• Write the DB2 SQL query to find the third highest ORDER_TOTAL in a ORDERS DB2 table
• How will you create a new TRIGGER on the ORDERS DB2 table? Give the syntax of TRIGGER
• Write a DB2 query to find out all the duplicate INVOICE_ID in ORDERS DB2 table?
• How will you find out all the indexes which are built in a particular DB2 table?
• How to find all the foreign keys of a DB2 table TAB1?
• What's the meaning of the phrase 'what you seek is seeking you'?
• How will you detect the condition of the end of cursor rows in a COBOL-DB2 program?
• How can you revert all the DB2 table changes done in a COBOL-DB2 program?
• Write the syntax to declare a scrollable cursor on the ORDERS DB2 table.
• Python – Average of digit greater than K
• Count the number of words having sum of ASCII values less than and greater than k in C++
• Find the Number of segments where all elements are greater than X using C++
• Write a SQL query to count the number of duplicate TRANSACTION_ID in an ORDERS DB2 table
• How to get the list of all COBOL-DB2 programs using a DB2 table TAB1?
• How to find the Average Values of all the Array Elements in C#?