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How to validate expiry date on a MySQL query?
You can use NOW() for this. Following is the syntax −
select * from yourTableName where yourColumnName> now();
Let us first create a table −
mysql> create table DemoTable ( Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, expiryDateOfMedicine datetime ); Query OK, 0 rows affected (0.55 sec)
Insert records in the table using insert command −
mysql> insert into DemoTable(expiryDateOfMedicine) values('2019-04-27 11:29:00');
Query OK, 1 row affected (0.36 sec)
mysql> insert into DemoTable(expiryDateOfMedicine) values('2019-04-26 10:39:21');
Query OK, 1 row affected (0.41 sec)
mysql> insert into DemoTable(expiryDateOfMedicine) values('2019-04-28 11:30:10');
Query OK, 1 row affected (0.18 sec)
mysql> insert into DemoTable(expiryDateOfMedicine) values('2019-04-29 12:44:11');
Query OK, 1 row affected (0.18 sec)Display all records from the table using select statement −
mysql> select * from DemoTable;
This will produce the following output −
+----+----------------------+ | Id | expiryDateOfMedicine | +----+----------------------+ | 1 | 2019-04-27 11:29:00 | | 2 | 2019-04-26 10:39:21 | | 3 | 2019-04-28 11:30:10 | | 4 | 2019-04-29 12:44:11 | +----+----------------------+ 4 rows in set (0.00 sec)
Following is the query to validate expiry date on a MySQL query −
mysql> select * from DemoTable where expiryDateOfMedicine > now();
This will produce the following output −
+----+----------------------+ | Id | expiryDateOfMedicine | +----+----------------------+ | 3 | 2019-04-28 11:30:10 | | 4 | 2019-04-29 12:44:11 | +----+----------------------+ 2 rows in set (0.00 sec)
Updated on: 30-Jul-2019
1K+ Views
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