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How to use use an array of pointers (Jagged) in C/C++?
Let us consider the following example, which uses an array of 3 integers −
In C
Example
#include <stdio.h>
const int MAX = 3;
int main () {
int var[] = {10, 100, 200};
int i;
for (i = 0; i < MAX; i++) {
printf("Value of var[%d] = %d\n", i, var[i] );
}
return 0;
}Output
Value of var[0] = 10 Value of var[1] = 100 Value of var[2] = 200
In C++
Example
#include <iostream>
using namespace std;
const int MAX = 3;
int main () {
int var[] = {10, 100, 200};
int i;
for (i = 0; i < MAX; i++) {
cout<<"Value of var"<<i<<"="<<var[i]<<"\n";
}
return 0;
}Output
Value of var0=10 Value of var1=100 Value of var2=200
There may be a situation when we want to maintain an array, which can store pointers to an int or char or any other data type available. Following is the declaration of an array of pointers to an integer −
int *ptr[MAX]
It declares ptr as an array of MAX integer pointers. Thus, each element in ptr, holds a pointer to an int value. The following example uses three integers, which are stored in an array of pointers, as follows −
In C
Example
#include <stdio.h>
const int MAX = 3;
int main () {
int var[] = {10, 100, 200};
int i, *ptr[MAX];
for ( i = 0; i < MAX; i++) {
ptr[i] = &var[i]; /* assign the address of integer. */
}
for ( i = 0; i < MAX; i++) {
printf("Value of var[%d] = %d\n", i, *ptr[i] );
}
return 0;
}Output
Value of var[0] = 10 Value of var[1] = 100 Value of var[2] = 200
In C++
Example
#include <iostream>
using namespace std;
const int MAX=3;
int main () {
int var[] = {10, 100, 200};
int i, *ptr[MAX];
for ( i = 0; i < MAX; i++) {
ptr[i] = &var[i]; /* assign the address of integer. */
}
for ( i = 0; i < MAX; i++) {
cout<<"Value of var" << i<<"="<<*ptr[i] <<"\n";
}
}Output
Value of var0=10 Value of var1=100 Value of var2=200
You can also use an array of pointers to character to store a list of strings as follows −
In C
Example
#include <stdio.h>
const int MAX = 4;
int main () {
char *names[] = {
"Zara Ali",
"Hina Ali",
"Nuha Ali",
"Sara Ali"
};
int i = 0;
for ( i = 0; i < MAX; i++) {
printf("Value of names[%d] = %s\n", i, names[i] );
}
return 0;
}Output
Value of names[0] = Zara Ali Value of names[1] = Hina Ali Value of names[2] = Nuha Ali Value of names[3] = Sara Ali
In C++
Example
#include <iostream>
using namespace std;
const int MAX=4;
int main () {
char *names[] = {
"Zara Ali",
"Hina Ali",
"Nuha Ali",
"Sara Ali"
};
int i = 0;
for ( i = 0; i < MAX; i++) {
cout<<"Value of names"<< i<<"="<< names[i]<<"\n";
}
return 0;
}Output
Value of names0=Zara Ali Value of names1=Hina Ali Value of names2=Nuha Ali Value of names3=Sara Ali
Updated on: 30-Jul-2019
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