How to use MySQL LIKE clause to fetch multiple values beginning with “Joh”


Let us first create a table −

mysql> create table DemoTable
(
   Name varchar(40)
);
Query OK, 0 rows affected (0.55 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable values('John');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Sam');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable values('Mike');
Query OK, 1 row affected (0.11 sec)
mysql> insert into DemoTable values('Ethan');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Johnson');
Query OK, 1 row affected (0.16 sec)
mysql> insert into DemoTable values('Bob');
Query OK, 1 row affected (0.12 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

This will produce the following output −

+---------+
| Name    |
+---------+
| John    |
| Sam     |
| Mike    |
| Ethan   |
| Johnson |
| Bob     |
+---------+
6 rows in set (0.00 sec)

Following is the query to fetch multiple values beginning with “Joh” −

mysql> select *from(
   select Name as myValue from DemoTable union
   select Name from DemoTable
)tbl
where myValue like 'Joh%';

This will produce the following output −

+---------+
| myValue |
+---------+
| John    |
| Johnson |
+---------+
2 rows in set (0.00 sec)
raja
Published on 07-Oct-2019 15:16:39
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