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How to use deleteOne() function in MongoDB?
The deleteOne() function in MongoDB deletes at most one matching document from a collection. Let us first create a collection with documents −
> db.demo363.insertOne({"Name":"Chris"}); { "acknowledged" : true, "insertedId" : ObjectId("5e57d2c3d0ada61456dc9369") } > db.demo363.insertOne({"Name":"David"}); { "acknowledged" : true, "insertedId" : ObjectId("5e57d2c7d0ada61456dc936a") } > db.demo363.insertOne({"Name":"Bob"}); { "acknowledged" : true, "insertedId" : ObjectId("5e57d2cad0ada61456dc936b") } > db.demo363.insertOne({"Name":"Chris"}); { "acknowledged" : true, "insertedId" : ObjectId("5e57d2d1d0ada61456dc936c") }
Display all documents from a collection with the help of find() method −
> db.demo363.find();
This will produce the following output −
{ "_id" : ObjectId("5e57d2c3d0ada61456dc9369"), "Name" : "Chris" } { "_id" : ObjectId("5e57d2c7d0ada61456dc936a"), "Name" : "David" } { "_id" : ObjectId("5e57d2cad0ada61456dc936b"), "Name" : "Bob" } { "_id" : ObjectId("5e57d2d1d0ada61456dc936c"), "Name" : "Chris" }
Following is the query to work with deleteOne() in MongoDB −
> db.demo363.deleteOne({Name:"Chris"}); { "acknowledged" : true, "deletedCount" : 1 }
Display all documents from a collection with the help of find() method −
> db.demo363.find();
This will produce the following output −
{ "_id" : ObjectId("5e57d2c7d0ada61456dc936a"), "Name" : "David" } { "_id" : ObjectId("5e57d2cad0ada61456dc936b"), "Name" : "Bob" } { "_id" : ObjectId("5e57d2d1d0ada61456dc936c"), "Name" : "Chris" }
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