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How to use a final or effectively final variable in lambda expression in Java?
The effectively final variables refer to local variables that are not declared final explicitly and can't be changed once initialized. A lambda expression can use a local variable in outer scopes only if they are effectively final.
Syntax
(optional) (Arguments) -> body
In the below example, the "size" variable is not declared as final but it's effective final because we are not modifying the value of the "size" variable.
Example
interface Employee {
void empData(String empName);
}
public class LambdaEffectivelyFinalTest {
public static void main(String[] args) {
int size = 100;
Employee emp = name -> { // lambda expression
System.out.println("The employee strength is: " + size);
System.out.println("The employee name is: " + name);
};
emp.empData("Adithya");
}
}Output
The employee strength is: 100 The employee name is: Adithya
Updated on: 10-Jul-2020
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