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How to query MongoDB a value with $lte and $in?
Let us first create a collection with documents −
> db.queryMongoValueDemo.insertOne(
{
_id:101,
"ScoreDetails":[{Score:80},{Score:45},{Score:25},{Score:70}]
}
);
{ "acknowledged" : true, "insertedId" : 101 }
> db.queryMongoValueDemo.insertOne(
{
_id:102,
"ScoreDetails":[{Score:80},{Score:24},{Score:34}]
}
);
{ "acknowledged" : true, "insertedId" : 102 }
> db.queryMongoValueDemo.insertOne(
{
_id:103,
"ScoreDetails":[{Score:99},{Score:95}]
}
);
{ "acknowledged" : true, "insertedId" : 103 }Display all documents from a collection with the help of find() method −
> db.queryMongoValueDemo.find().pretty();
This will produce the following output −
{
"_id" : 101,
"ScoreDetails" : [
{
"Score" : 80
},
{
"Score" : 45
},
{
"Score" : 25
},
{
"Score" : 70
}
]
}
{
"_id" : 102,
"ScoreDetails" : [
{
"Score" : 80
},
{
"Score" : 24
},
{
"Score" : 34
}
]
}
{
"_id" : 103,
"ScoreDetails" : [
{
"Score" : 99
},
{
"Score" : 95
}
]
}Query for $lte and $in operator implemented by $not along with $gt operator −
> db.queryMongoValueDemo.find({
"ScoreDetails.Score": {
"$eq": 80,
"$not": { "$gt": 80 }
}
});This will produce the following output −
{ "_id" : 101, "ScoreDetails" : [ { "Score" : 80 }, { "Score" : 45 }, { "Score" : 25 }, { "Score" : 70 } ] }
{ "_id" : 102, "ScoreDetails" : [ { "Score" : 80 }, { "Score" : 24 }, { "Score" : 34 } ] }
Updated on: 30-Jul-2019
75 Views
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