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How to print all students name having percentage more than 70% in JavaScript?
You can use a for loop and check whether the percentage is greater than 70 or not with if condition.
Following are the records of each student −
const studentDetails= [ { studentName:"John", percentage:78 }, { studentName:"Sam", percentage:68 }, { studentName:"Mike", percentage:88 }, { studentName:"Bob", percentage:70 } ]
Now, use the for loop and et conditions for students with percentage more than 70 −
for(var index=0;index<studentDetails.length;index++) { if(studentDetails[index].percentage > 70) { // } }
Example
const studentDetails= [ { studentName:"John", percentage:78 }, { studentName:"Sam", percentage:68 }, { studentName:"Mike", percentage:88 }, { studentName:"Bob", percentage:70 } ] for(var index=0;index<studentDetails.length;index++){ if(studentDetails[index].percentage > 70){ console.log("Student Name which has more than 70 %="+studentDetails[index].studentName); } }
To run the above program, you need to use the following command −
node fileName.js.
Here, my file name is demo68.js. This will produce the following output −
PS C:\Users\Amit\JavaScript-code> node demo68.js Student Name which has more than 70 %=John Student Name which has more than 70 %=Mike
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