- Data Structure
- Networking
- RDBMS
- Operating System
- Java
- MS Excel
- iOS
- HTML
- CSS
- Android
- Python
- C Programming
- C++
- C#
- MongoDB
- MySQL
- Javascript
- PHP
- Physics
- Chemistry
- Biology
- Mathematics
- English
- Economics
- Psychology
- Social Studies
- Fashion Studies
- Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
How to print all students name having percentage more than 70% in JavaScript?
You can use a for loop and check whether the percentage is greater than 70 or not with if condition.
Following are the records of each student −
const studentDetails= [ { studentName:"John", percentage:78 }, { studentName:"Sam", percentage:68 }, { studentName:"Mike", percentage:88 }, { studentName:"Bob", percentage:70 } ]
Now, use the for loop and et conditions for students with percentage more than 70 −
for(var index=0;index<studentDetails.length;index++) { if(studentDetails[index].percentage > 70) { // } }
Example
const studentDetails= [ { studentName:"John", percentage:78 }, { studentName:"Sam", percentage:68 }, { studentName:"Mike", percentage:88 }, { studentName:"Bob", percentage:70 } ] for(var index=0;index<studentDetails.length;index++){ if(studentDetails[index].percentage > 70){ console.log("Student Name which has more than 70 %="+studentDetails[index].studentName); } }
To run the above program, you need to use the following command −
node fileName.js.
Here, my file name is demo68.js. This will produce the following output −
PS C:\Users\Amit\JavaScript-code> node demo68.js Student Name which has more than 70 %=John Student Name which has more than 70 %=Mike
Advertisements