# How to print all students name having percentage more than 70% in JavaScript?

JavascriptWeb DevelopmentObject Oriented Programming

You can use a for loop and check whether the percentage is greater than 70 or not with if condition.

Following are the records of each student −

const studentDetails=
[
{
studentName:"John",
percentage:78
},
{
studentName:"Sam",
percentage:68
},
{
studentName:"Mike",
percentage:88
},
{
studentName:"Bob",
percentage:70
}
]

Now, use the for loop and et conditions for students with percentage more than 70 −

for(var index=0;index<studentDetails.length;index++)
{
if(studentDetails[index].percentage > 70)
{
//
}
}

## Example

const studentDetails=
[
{
studentName:"John",
percentage:78
},
{
studentName:"Sam",
percentage:68
},
{
studentName:"Mike",
percentage:88
},
{
studentName:"Bob",
percentage:70
}
]
for(var index=0;index<studentDetails.length;index++){
if(studentDetails[index].percentage > 70){
console.log("Student Name which has more than 70
%="+studentDetails[index].studentName);
}
}

To run the above program, you need to use the following command −

node fileName.js.

Here, my file name is demo68.js. This will produce the following output −

PS C:\Users\Amit\JavaScript-code> node demo68.js
Student Name which has more than 70 %=John
Student Name which has more than 70 %=Mike
Published on 03-Sep-2020 07:40:00