How to print a semicolon(;) without using semicolon in C/C++?

In this tutorial, we will be discussing a program to understand how to print a semicolon(;) without using a semicolon in /C++.

This can be done in two possible ways, either by using the ascii value of semicolon or using user-defined macros for the same.

Example

 Live Demo

Using putchar() method

#include <stdio.h>
int main(){
   //ASCII value of semicolon is equal to 59
   if (putchar(59)){
   }
   return 0;
}

Output

;

Example

 Live Demo

Using Macros :

#include <stdio.h>
#define POINT printf("%c",59)
int main(){
   if (POINT) {
   }
}

Output

;

Ayush Gupta

Updated on 02-Mar-2020 10:38:18

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