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How to pass individual elements in an array as argument to function in C language?
If individual elements are to be passed as arguments, then array elements along with their subscripts must be given in function call.
To receive the elements, simple variables are used in function definition.
Example 1
#include<stdio.h>
main (){
void display (int, int);
int a[5], i;
clrscr();
printf (“enter 5 elements”);
for (i=0; i<5; i++)
scanf("%d", &a[i]);
display (a [0], a[4]); //calling function with individual arguments
getch( );
}
void display (int a, int b){ //called function with individual arguments
print f ("first element = %d",a);
printf ("last element = %d",b);
}Output
Enter 5 elements 10 20 30 40 50 First element = 10 Last element = 50
Example 2
Consider another example for passing individual elements as argument to a function.
#include<stdio.h>
main (){
void arguments(int,int);
int a[10], i;
printf ("enter 6 elements:
");
for (i=0; i<6; i++)
scanf("%d", &a[i]);
arguments(a[0],a[5]); //calling function with individual arguments
getch( );
}
void arguments(int a, int b){ //called function with individual arguments
printf ("first element = %d
",a);
printf ("last element = %d
",b);
}Output
enter 6 elements: 1 2 3 4 5 6 first element = 1 last element = 6
Updated on: 09-Mar-2021
1K+ Views
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