How to implement ToLongBiFunction<T, U> using lambda expression in Java?

Java 8Object Oriented ProgrammingProgramming

ToLongBiFunction<T, U> is a in-built functional interface from java.util.function package. This functional interface accepts two reference type parameters as input and produces a long-valued result. ToLongBiFunction<T, U> interface can be used as an assignment target for a lambda expression or method reference and contains only one abstract method: applyAsLong().

Syntax

@FunctionalInterface
interface ToLongBiFunction<T, U> {
 long applyAsLong(T t, U u);
}

Example

import java.util.*;
import java.util.function.ToLongBiFunction;

public class ToLongBiFunctionTest {
   public static void main(String[] args) {
      ToLongBiFunction<Map<String, Long>, String> getMobileNum = (map,value) -> {    // lambda
         if(map != null && !map.isEmpty()) {
            if(map.containsKey(value)) {
               return map.get(value);
            }
         }
         return 0;
      };
      Map<String, Long> mobileNumbers = new HashMap<String, Long>();
      mobileNumbers.put("Raja", 9959984805L);
      mobileNumbers.put("Adithya", 7702144433L);
      mobileNumbers.put("Jai", 7013536286L);
      mobileNumbers.put("Chaitanya", 9652671506L);

      String name = "Raja";
      long result = getMobileNum.applyAsLong(mobileNumbers, name);
      System.out.println("Raja's Mobile no: "+ result);

      name = "Adithya";
      System.out.println("Adithya's Mobile no: "+ getMobileNum.applyAsLong(mobileNumbers, name));

      name = "Jai";
      System.out.println("Jai's Mobile no: "+ getMobileNum.applyAsLong(mobileNumbers, name));

      name = "Chaitanya";
      System.out.println("Chaitanya's Mobile no: "+ getMobileNum.applyAsLong(mobileNumbers, name));
   }
}

Output

Raja's Mobile no: 9959984805
Adithya's Mobile no: 7702144433
Jai's Mobile no: 7013536286
Chaitanya's Mobile no: 9652671506
raja
Published on 24-Jan-2020 10:08:18
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