Data Structure
Networking
RDBMS
Operating System
Java
MS Excel
iOS
HTML
CSS
Android
Python
C Programming
C++
C#
MongoDB
MySQL
Javascript
PHP
Physics
Chemistry
Biology
Mathematics
English
Economics
Psychology
Social Studies
Fashion Studies
Legal Studies
- Selected Reading
- UPSC IAS Exams Notes
- Developer's Best Practices
- Questions and Answers
- Effective Resume Writing
- HR Interview Questions
- Computer Glossary
- Who is Who
How to implement ToIntFunction using lambda and method reference in Java?
ToIntFunction<T> is the built-in functional interface defined in java.util.function package. This functional interface expects an argument as input and produces an int-valued result. It can be used as an assignment target for a lambda expression or method reference. The ToIntFunction interface holds only one method, applyAsInt(). This method performs an operation on the given argument and returns the int-valued result.
Syntax
@FunctionalInterface
public interface ToIntFunction {
int applyAsInt(T value);
}In the below example, we can implement ToIntFunction<T> by using lambda expression and method reference.
Example
import java.util.function.ToIntFunction;
import java.time.LocalDate;
public class ToIntFunctionInterfaceTest {
public static void main(String[] args) {
ToIntFunction<Integer> lambdaObj = value -> value * 25; // using lambda expression
System.out.println("The result is: " + lambdaObj.applyAsInt(10));
ToIntFunction<String> lenFn = String::length; // using method reference
System.out.println("The length of a String is: " + lenFn.applyAsInt("tutorialspoint"));
}
}Output
The result is: 250 The length of a String is: 14
Updated on: 13-Jul-2020
454 Views
Advertisements