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How to implement the ObjIntConsumer interface using lambda expression in Java?
The ObjIntConsumer interface is a kind of functional interface and defined in java.util.function package. This functional interface expects an object-valued and int-valued argument as input and does not produce any output. It holds only one functional method, accept(Object, int).
Syntax
@FunctionalInterface
public interface ObjIntConsumer {
void accept(T t, int value)
}In the below examples, we can implement the ObjIntConsumer interface by using a lambda expression.
Example-1
import java.util.function.*;
public class ObjIntConsumerInterfaceTest1 {
public static void main(String args[]) {
ObjIntConsumer<String> objIntConsumberObj = (t, value) -> { // lambda expression
if(t.length() > value) {
System.out.println("String is bigger than the expected value");
} else if(t.length() == value) {
System.out.println("String is equal to expected value");
} else {
System.out.println("String is shorter than the expected value");
}
}; // end of lambda expression
objIntConsumberObj.accept("tutorialspoint.com", 15);
objIntConsumberObj.accept("tutorix.com", 15);
}
}Output
String is bigger than the expected value String is shorter than the expected value
Example-2
import java.util.*;
import java.util.function.*;
public class ObjIntConsumerInterfaceTest2 {
public static void main(String args[]) {
ObjIntConsumer<List <Integer>> objIntConsumberObj = (t, value) -> { // lamnda expression
if(t.contains(value)) {
System.out.println("Expected value is present in the string");
} else {
System.out.println("Expected value is not present in the string");
}
}; // end of lambda expression
List<Integer> listObj = new ArrayList<Integer>();
listObj.add(55);
listObj.add(100);
listObj.add(75);
objIntConsumberObj.accept(listObj, 80);
objIntConsumberObj.accept(listObj, 100);
}
}Output
Expected value is not present in the string Expected value is present in the string
Updated on: 13-Jul-2020
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