How to get odd and even position characters from a string?

We have to write a function that removes every second character (starting from the very first character) from a string and appends all of those removed characters at the end in JavaScript.

For example −

If the string is "This is a test!"
Then it should become "hsi etTi sats!"

Therefore, let’s write the code for this function −

Example

const string = 'This is a test!';
const separateString = (str) => {
   const { first, second } = [...str].reduce((acc, val, ind) => {
      const { first, second } = acc;
      return {
         first: ind % 2 === 1 ? first+val : first,
         second: ind % 2 === 0 ? second+val : second
      };
   }, {
      first: '',
      second: ''
   })
   return first+second;
};
console.log(separateString(string));

Output

The output in the console will be −

hsi etTi sats!

AmitDiwan

Published on 24-Aug-2020 09:43:36

• Related Questions & Answers
• Converting Odd and Even-indexed characters in a string to uppercase/lowercase in JavaScript?
• Difference between sums of odd position and even position nodes of a Binary Tree in Java
• Java program to print odd and even number from a Java array.
• How to get last 4 characters from string in C#?
• Java program to Print Odd and Even Number from an Array
• Even numbers at even index and odd numbers at odd index in C++
• Separate odd and even in JavaScript
• Count Odd and Even numbers in a range from L to R in C++
• Sum of individual even and odd digits in a string number using JavaScript
• Missing even and odd elements from the given arrays in C++
• MySQL query to get a single value from position of comma-separated string?
• Sorting odd and even elements separately JavaScript
• How to get last 2 characters from string in C# using Regex?
• How to extract characters from a string in R?
• How to Remove Characters from a String in Arduino?