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How to get an age from a D.O.B field in MySQL?
To get age from a D.O.B field in MySQL, you can use the following syntax. Here, we subtract the DOB from the current date.
select yourColumnName1,yourColumnName2,........N,year(curdate())- year(yourDOBColumnName) as anyVariableName from yourTableName;
To understand the above syntax, let us first create a table. The query to create a table is as follows.
mysql> create table AgeDemo -> ( -> StudentId int, -> StudentName varchar(100), -> StudentDOB date -> ); Query OK, 0 rows affected (0.61 sec)
Insert some records in the table using insert command. The query is as follows.
mysql> insert into AgeDemo values(1,'John','1998-10-1'); Query OK, 1 row affected (0.20 sec) mysql> insert into AgeDemo values(2,'Carol','1990-1-2'); Query OK, 1 row affected (0.14 sec) mysql> insert into AgeDemo values(3,'Sam','2000-12-1'); Query OK, 1 row affected (0.15 sec) mysql> insert into AgeDemo values(4,'Mike','2010-10-11'); Query OK, 1 row affected (0.18 sec)
Display all records from the table using select statement. The query is as follows.
mysql> select *from AgeDemo;
The following is the output.
+-----------+-------------+------------+ | StudentId | StudentName | StudentDOB | +-----------+-------------+------------+ | 1 | John | 1998-10-01 | | 2 | Carol | 1990-01-02 | | 3 | Sam | 2000-12-01 | | 4 | Mike | 2010-10-11 | +-----------+-------------+------------+ 4 rows in set (0.00 sec)
Here is the query to calculate the age from D.O.B. The query is as follows.
mysql> select StudentName,StudentDOB,year(curdate())-year(StudentDOB) as StudentAge from AgeDemo;
The following is the output displaying age.
+-------------+------------+------------+ | StudentName | StudentDOB | StudentAge | +-------------+------------+------------+ | John | 1998-10-01 | 21 | | Carol | 1990-01-02 | 29 | | Sam | 2000-12-01 | 19 | | Mike | 2010-10-11 | 9 | +-------------+------------+------------+ 4 rows in set (0.03 sec)
Updated on: 30-Jul-2019
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