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How to get a rating average in MongoDB based on duplicate ids?
For average in MongoDB, use the $avg. Let us create a collection with documents. Here, we have duplicate ids with rating for each −
> db.demo606.insertOne({id:1,rating:5});{
"acknowledged" : true, "insertedId" : ObjectId("5e972dfbf57d0dc0b182d623")
}
> db.demo606.insertOne({id:1,rating:4});{
"acknowledged" : true, "insertedId" : ObjectId("5e972dfef57d0dc0b182d624")
}
> db.demo606.insertOne({id:2,rating:3});{
"acknowledged" : true, "insertedId" : ObjectId("5e972e09f57d0dc0b182d625")
}
> db.demo606.insertOne({id:1,rating:null});{
"acknowledged" : true, "insertedId" : ObjectId("5e972e0ef57d0dc0b182d626")
}
> db.demo606.insertOne({id:2,rating:null});{
"acknowledged" : true, "insertedId" : ObjectId("5e972e15f57d0dc0b182d627")
}
> db.demo606.insertOne({id:2,rating:3});{
"acknowledged" : true, "insertedId" : ObjectId("5e972e1bf57d0dc0b182d628")
}Display all documents from a collection with the help of find() method −
> db.demo606.find();
This will produce the following output −
{ "_id" : ObjectId("5e972dfbf57d0dc0b182d623"), "id" : 1, "rating" : 5 }
{ "_id" : ObjectId("5e972dfef57d0dc0b182d624"), "id" : 1, "rating" : 4 }
{ "_id" : ObjectId("5e972e09f57d0dc0b182d625"), "id" : 2, "rating" : 3 }
{ "_id" : ObjectId("5e972e0ef57d0dc0b182d626"), "id" : 1, "rating" : null }
{ "_id" : ObjectId("5e972e15f57d0dc0b182d627"), "id" : 2, "rating" : null }
{ "_id" : ObjectId("5e972e1bf57d0dc0b182d628"), "id" : 2, "rating" : 3 }Following is the query to get rating average based on duplicate ids −
> db.demo606.aggregate(
... [
... { "$group": {
... "_id": "$id",
... "AverageRating": { "$avg": { "$ifNull": ["$rating",0 ] } }
... }}
... ]
... );This will produce the following output −
{ "_id" : 2, "AverageRating" : 2 }
{ "_id" : 1, "AverageRating" : 3 }
Updated on: 15-May-2020
246 Views
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