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How to find all records which are NOT in the set array with MySQL?
For this, you can use NOT IN() function.
Let us first create a table −
mysql> create table DemoTable718 ( Id int, FirstName varchar(100), Age int ); Query OK, 0 rows affected (0.59 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable718 values(101,'Chris',26); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable718 values(102,'Robert',24); Query OK, 1 row affected (0.13 sec) mysql> insert into DemoTable718 values(103,'David',27); Query OK, 1 row affected (0.16 sec) mysql> insert into DemoTable718 values(104,'Mike',28); Query OK, 1 row affected (0.19 sec) mysql> insert into DemoTable718 values(105,'Sam',23); Query OK, 1 row affected (0.14 sec)
Display all records from the table using select statement −
mysql> select *from DemoTable718;
This will produce the following output -
+------+-----------+------+ | Id | FirstName | Age | +------+-----------+------+ | 101 | Chris | 26 | | 102 | Robert | 24 | | 103 | David | 27 | | 104 | Mike | 28 | | 105 | Sam | 23 | +------+-----------+------+ 5 rows in set (0.00 sec)
Here is the query to find all records which are NOT in the set array −
mysql> select *from DemoTable718 where Id NOT IN('101','103','104');This will produce the following output -
+------+-----------+------+ | Id | FirstName | Age | +------+-----------+------+ | 102 | Robert | 24 | | 105 | Sam | 23 | +------+-----------+------+ 2 rows in set (0.00 sec)
Updated on: 22-Aug-2019
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