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How to find a specific record from a list of values with semicolon in MySQL?
For this, you can use FIND_IN_SET(). Let us first create a table −
mysql> create table DemoTable ( Id int NOT NULL AUTO_INCREMENT PRIMARY KEY, Value varchar(100) ); Query OK, 0 rows affected (2.49 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable(Value) values('100;200;300');
Query OK, 1 row affected (0.42 sec)
mysql> insert into DemoTable(Value) values('1;300;400');
Query OK, 1 row affected (0.58 sec)
mysql> insert into DemoTable(Value) values('6;7;8;9;10');
Query OK, 1 row affected (0.29 sec)
mysql> insert into DemoTable(Value) values('1;2;3;4;5');
Query OK, 1 row affected (9.36 sec)
mysql> insert into DemoTable(Value) values('3;8;9;10');
Query OK, 1 row affected (0.46 sec)Display all records from the table using select statement −
mysql> select *from DemoTable;
This will produce the following output −
+----+-------------+ | Id | Value | +----+-------------+ | 1 | 100;200;300 | | 2 | 1;300;400 | | 3 | 6;7;8;9;10 | | 4 | 1;2;3;4;5 | | 5 | 3;8;9;10 | +----+-------------+ 5 rows in set (0.00 sec)
Following is the query to find a specific record from a list of values with a semicolon −
mysql> select *from DemoTable where find_in_set(8, replace(Value, ';', ',')) > 0;
This will produce the following output −
+----+------------+ | Id | Value | +----+------------+ | 3 | 6;7;8;9;10 | | 5 | 3;8;9;10 | +----+------------+ 2 rows in set (0.00 sec)
Updated on: 26-Sep-2019
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