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How to count the number of repeated characters in a Golang String?
Count() is a built-in function is Golang that can be used to count the number of non-overlapping instances of a character/string in a string.
Syntax
func Count(s, sep string) int
Where,
s – Original String
sep – Substring which we want to count.
It returns an Integer value.
Example
The following example demonstrates how you can use the Count() function in a Go program.
package main
import (
"fmt"
"strings"
)
func main() {
// Initializing the Strings
x := "Golang Programming Language"
y := "Language"
// Display the Strings
fmt.Println("First String:", x)
fmt.Println("Second String:", y)
// Using Count Function
test1 := strings.Count(x, "g")
test2 := strings.Count(y, "b")
// Diplay the Count Output
fmt.Println("Count of 'g' in the First String:", test1)
fmt.Println("Count of 'b' in the Second String:", test2)
}
Output
On execution, it will produce the following output −
First String: Golang Programming Language Second String: Language Count of 'g' in the First String: 5 Count of 'b' in the Second String: 0
Example
Let us take another example −
package main
import (
"fmt"
"strings"
)
func main() {
// Initializing the Strings
p := "Hyderabad"
q := "Country"
r := "Chennai"
s := "Pune"
// Display the Strings
fmt.Println("First String:", p)
fmt.Println("Second String:", q)
fmt.Println("Third String:", r)
fmt.Println("Fourth String:", s)
// Using the Count Function
w := strings.Count(p, "d")
x := strings.Count(q, "t")
y := strings.Count(r, "n")
z := strings.Count(s, "e")
// Display the Count Output
fmt.Println("Count of 'd' in First String:", w)
fmt.Println("Count of 't' in Second String:", x)
fmt.Println("Count of 'n' in Third String:", y)
fmt.Println("Count of 's' in Fourth String:", z)
}
Output
It will produce the following output −
First String: Hyderabad Second String: Country Third String: Chennai Fourth String: Pune Count of 'd' in First String: 2 Count of 't' in Second String: 1 Count of 'n' in Third String: 2 Count of 's' in Fourth String: 1
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