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How to count the number of repeated characters in a Golang String?
Count() is a built-in function is Golang that can be used to count the number of non-overlapping instances of a character/string in a string.
Syntax
func Count(s, sep string) int
Where,
s – Original String
sep – Substring which we want to count.
It returns an Integer value.
Example
The following example demonstrates how you can use the Count() function in a Go program.
package main import ( "fmt" "strings" ) func main() { // Initializing the Strings x := "Golang Programming Language" y := "Language" // Display the Strings fmt.Println("First String:", x) fmt.Println("Second String:", y) // Using Count Function test1 := strings.Count(x, "g") test2 := strings.Count(y, "b") // Diplay the Count Output fmt.Println("Count of 'g' in the First String:", test1) fmt.Println("Count of 'b' in the Second String:", test2) }
Output
On execution, it will produce the following output −
First String: Golang Programming Language Second String: Language Count of 'g' in the First String: 5 Count of 'b' in the Second String: 0
Example
Let us take another example −
package main import ( "fmt" "strings" ) func main() { // Initializing the Strings p := "Hyderabad" q := "Country" r := "Chennai" s := "Pune" // Display the Strings fmt.Println("First String:", p) fmt.Println("Second String:", q) fmt.Println("Third String:", r) fmt.Println("Fourth String:", s) // Using the Count Function w := strings.Count(p, "d") x := strings.Count(q, "t") y := strings.Count(r, "n") z := strings.Count(s, "e") // Display the Count Output fmt.Println("Count of 'd' in First String:", w) fmt.Println("Count of 't' in Second String:", x) fmt.Println("Count of 'n' in Third String:", y) fmt.Println("Count of 's' in Fourth String:", z) }
Output
It will produce the following output −
First String: Hyderabad Second String: Country Third String: Chennai Fourth String: Pune Count of 'd' in First String: 2 Count of 't' in Second String: 1 Count of 'n' in Third String: 2 Count of 's' in Fourth String: 1
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