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How to aggregate sum in MongoDB to get the total count?
To aggregate sum in MongoDB to get the total count, you can use the $sum operator. To understand the above concept, let us create a collection with the document −
> db.aggregateSumDemo.insertOne({"CustomerName":"Larry","Amount":140});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c8baa0680f10143d8431e18")
}
> db.aggregateSumDemo.insertOne({"CustomerName":"Mike","Amount":160});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c8baa1380f10143d8431e19")
}
> db.aggregateSumDemo.insertOne({"CustomerName":"Sam","Amount":300});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c8baa1c80f10143d8431e1a")
}
> db.aggregateSumDemo.insertOne({"CustomerName":"David","Amount":500});
{
"acknowledged" : true,
"insertedId" : ObjectId("5c8baa2580f10143d8431e1b")
}Display all documents from a collection with the help of find() method. The query is as follows −
> db.aggregateSumDemo.find().pretty();
The following is the output −
{
"_id" : ObjectId("5c8baa0680f10143d8431e18"),
"CustomerName" : "Larry",
"Amount" : 140
}
{
"_id" : ObjectId("5c8baa1380f10143d8431e19"),
"CustomerName" : "Mike",
"Amount" : 160
}
{
"_id" : ObjectId("5c8baa1c80f10143d8431e1a"),
"CustomerName" : "Sam",
"Amount" : 300
}
{
"_id" : ObjectId("5c8baa2580f10143d8431e1b"),
"CustomerName" : "David",
"Amount" : 500
}Here is the query to get the total count.
Case 1 − The query is as follows −
> db.aggregateSumDemo.aggregate([ {
... $group: {
... _id: null,
... "TotalCount": {
... $sum:1
... }
... }
... } ] );The following is the output −
{ "_id" : null, "TotalCount" : 4 }Here is the query to aggregate sum in MongoDB to get the total sum.
Case 2 − The query is as follows −
> db.aggregateSumDemo.aggregate([ {
... $group: {
... _id: null,
... "TotalAmount": {
... $sum: "$Amount"
... }
... }
... } ] );The following is the output −
{ "_id" : null, "TotalAmount" : 1100 }
Updated on: 30-Jul-2019
761 Views
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