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How can I sort documents in MongoDB 4 and display only a single field?
To sort documents in MongoDB 4, use sort(). To show only a single field, which is sorted, set it to 1.
Let us create a collection with documents −
> db.demo611.insertOne({"Name":"Chris"});{
"acknowledged" : true, "insertedId" : ObjectId("5e987110f6b89257f5584d83")
}
> db.demo611.insertOne({"Name":"Adam"});{
"acknowledged" : true, "insertedId" : ObjectId("5e987115f6b89257f5584d84")
}
> db.demo611.insertOne({"Name":"John"});{
"acknowledged" : true, "insertedId" : ObjectId("5e987118f6b89257f5584d85")
}
> db.demo611.insertOne({"Name":"Bob"});{
"acknowledged" : true, "insertedId" : ObjectId("5e98711bf6b89257f5584d86")
}Display all documents from a collection with the help of find() method −
> db.demo611.find();
This will produce the following output:
{ "_id" : ObjectId("5e987110f6b89257f5584d83"), "Name" : "Chris" }
{ "_id" : ObjectId("5e987115f6b89257f5584d84"), "Name" : "Adam" }
{ "_id" : ObjectId("5e987118f6b89257f5584d85"), "Name" : "John" }
{ "_id" : ObjectId("5e98711bf6b89257f5584d86"), "Name" : "Bob" }Following is the query to sort documents using MongoDB 4 −
> db.demo611.find().sort({Name:1});This will produce the following output &mius;
{ "_id" : ObjectId("5e987115f6b89257f5584d84"), "Name" : "Adam" }
{ "_id" : ObjectId("5e98711bf6b89257f5584d86"), "Name" : "Bob" }
{ "_id" : ObjectId("5e987110f6b89257f5584d83"), "Name" : "Chris" }
{ "_id" : ObjectId("5e987118f6b89257f5584d85"), "Name" : "John" }
Updated on: 15-May-2020
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