How can I select rows which fall on a specific day of week in MySQL?
For specific day of week, use DAYOFWEEK().
Let us first create a table −
mysql> create table DemoTable785 (
CustomerId int NOT NULL AUTO_INCREMENT PRIMARY KEY,
CustomerName varchar(100),
ShoppingDate date
);
Query OK, 0 rows affected (0.61 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Chris','2019-07-03');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Robert','2019-07-01');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('David','2019-07-06');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Carol','2019-07-19');
Query OK, 1 row affected (0.19 sec)Display all records from the table using select statement −
mysql> select *from DemoTable785;
This will produce the following output -
+------------+--------------+--------------+
| CustomerId | CustomerName | ShoppingDate |
+------------+--------------+--------------+
| 1 | Chris | 2019-07-03 |
| 2 | Robert | 2019-07-01 |
| 3 | David | 2019-07-06 |
| 4 | Carol | 2019-07-19 |
+------------+--------------+--------------+
4 rows in set (0.00 sec)
Following is the query to select rows which fall on a specific day of week −
mysql> select *from DemoTable785 where DAYOFWEEK(ShoppingDate)=2;
This will produce the following output -
+------------+--------------+--------------+
| CustomerId | CustomerName | ShoppingDate |
+------------+--------------+--------------+
| 2 | Robert | 2019-07-01 |
+------------+--------------+--------------+
1 row in set (0.00 sec)
Published on 09-Sep-2019 12:01:15
