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How can I select rows which fall on a specific day of week in MySQL?
For specific day of week, use DAYOFWEEK().
Let us first create a table −
mysql> create table DemoTable785 ( CustomerId int NOT NULL AUTO_INCREMENT PRIMARY KEY, CustomerName varchar(100), ShoppingDate date ); Query OK, 0 rows affected (0.61 sec)
Insert some records in the table using insert command −
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Chris','2019-07-03');
Query OK, 1 row affected (0.20 sec)
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Robert','2019-07-01');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('David','2019-07-06');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Carol','2019-07-19');
Query OK, 1 row affected (0.19 sec)Display all records from the table using select statement −
mysql> select *from DemoTable785;
This will produce the following output -
+------------+--------------+--------------+ | CustomerId | CustomerName | ShoppingDate | +------------+--------------+--------------+ | 1 | Chris | 2019-07-03 | | 2 | Robert | 2019-07-01 | | 3 | David | 2019-07-06 | | 4 | Carol | 2019-07-19 | +------------+--------------+--------------+ 4 rows in set (0.00 sec)
Following is the query to select rows which fall on a specific day of week −
mysql> select *from DemoTable785 where DAYOFWEEK(ShoppingDate)=2;
This will produce the following output -
+------------+--------------+--------------+ | CustomerId | CustomerName | ShoppingDate | +------------+--------------+--------------+ | 2 | Robert | 2019-07-01 | +------------+--------------+--------------+ 1 row in set (0.00 sec)
Updated on: 09-Sep-2019
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