HCF of co-prime numbers 4 and 15 was found as follows by factorisation:
$4 = 2 \times 2$ and $15 = 3 \times 5$ since there is no common prime factor, so HCF of 4 and 15 is 0. Is the answer correct? If not, what is the correct HCF?

Given:

$4 = 2 \times 2$ and $15 = 3 \times 5$ since there is no common prime factor, so HCF of 4 and 15 is 0. 

To do:

We have to find whether the answer is correct.

Solution:

$4=2\times2\times1$

$15=3\times5\times1$

Here,

The HCF of 4 and 15 is 1.

The given answer is not correct.

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Updated on: 10-Oct-2022

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