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Get the unqualified name of a class in Java
A qualified class name in Java contains the package that the class originated from. In contrast to this, the unqualified class name contains only the class name without any package information.
A program that gets the unqualified name of a class is given as follows:
Example
public class Demo {
public static void main(String[] argv) throws Exception {
Class c = java.util.ArrayList.class;
String className = c.getName();
System.out.println("The qualified class name is: " + className);
if (className.lastIndexOf('.') < 0) {
className = className.substring(className.lastIndexOf('.') + 1);
className = className.replace('$', '.');
}
System.out.println("The unqualified class name is: " + className);
}
}Output
The qualified class name is: java.util.ArrayList The unqualified class name is: ArrayList
Now let us understand the above program.
First the qualified class name is displayed using the getName() method. A code snippet which demonstrates this is as follows −
Class c = java.util.ArrayList.class;
String className = c.getName();
System.out.println("The qualified class name is: " + className);The unqualified class name is obtained using the substring() method that provides the substring of the className from the last index of ‘.’ Then the unqualified class name is displayed. A code snippet which demonstrates this is as follows −
if (className.lastIndexOf('.') < 0) {
className = className.substring(className.lastIndexOf('.') + 1);
className = className.replace('$', '.');
}
System.out.println("The unqualified class name is: " + className);
Updated on: 25-Jun-2020
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