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Get the returned record set ordered by (ORDER BY) position in MySQL 'IN' clause
To return record set order, you need to use FIND_IN_SET(). Let us first create a table −
mysql> create table recordSetOrderDemo -> ( -> EmployeeId int, -> EmployeeName varchar(30) -> ); Query OK, 0 rows affected (0.63 sec)
Following is the query to insert some records in the table using insert command −
mysql> insert into recordSetOrderDemo values(20,"John"); Query OK, 1 row affected (0.20 sec) mysql> insert into recordSetOrderDemo values(10,"Larry"); Query OK, 1 row affected (0.14 sec) mysql> insert into recordSetOrderDemo values(100,"Mike"); Query OK, 1 row affected (0.14 sec) mysql> insert into recordSetOrderDemo values(50,"Sam"); Query OK, 1 row affected (0.11 sec) mysql> insert into recordSetOrderDemo values(10,"David"); Query OK, 1 row affected (0.18 sec)
Following is the query to display all records from the table using select statement −
mysql> select *from recordSetOrderDemo;
This will produce the following output −
+------------+--------------+ | EmployeeId | EmployeeName | +------------+--------------+ | 20 | John | | 10 | Larry | | 100 | Mike | | 50 | Sam | | 10 | David | +------------+--------------+ 5 rows in set (0.00 sec)
Following is the query to return record set order −
mysql> select *from recordSetOrderDemo where EmployeeId IN(100,10,20,50) -> ORDER BY FIND_IN_SET(EmployeeId,'100,10,20,50');
This will produce the following output −
+------------+--------------+ | EmployeeId | EmployeeName | +------------+--------------+ | 100 | Mike | | 10 | Larry | | 10 | David | | 20 | John | | 50 | Sam | +------------+--------------+ 5 rows in set (0.03 sec)
Updated on: 30-Jul-2019
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