Get the returned record set ordered by (ORDER BY) position in MySQL 'IN' clause

To return record set order, you need to use FIND_IN_SET(). Let us first create a table −

mysql> create table recordSetOrderDemo
   -> (
   -> EmployeeId int,
   -> EmployeeName varchar(30)
   -> );
Query OK, 0 rows affected (0.63 sec)

Following is the query to insert some records in the table using insert command −

mysql> insert into recordSetOrderDemo values(20,"John");
Query OK, 1 row affected (0.20 sec)

mysql> insert into recordSetOrderDemo values(10,"Larry");
Query OK, 1 row affected (0.14 sec)

mysql> insert into recordSetOrderDemo values(100,"Mike");
Query OK, 1 row affected (0.14 sec)

mysql> insert into recordSetOrderDemo values(50,"Sam");
Query OK, 1 row affected (0.11 sec)

mysql> insert into recordSetOrderDemo values(10,"David");
Query OK, 1 row affected (0.18 sec)

Following is the query to display all records from the table using select statement −

mysql> select *from recordSetOrderDemo;

This will produce the following output −

+------------+--------------+
| EmployeeId | EmployeeName |
+------------+--------------+
| 20         | John         |
| 10         | Larry        |
| 100        | Mike         |
| 50         | Sam          |
| 10         | David        |
+------------+--------------+
5 rows in set (0.00 sec)

Following is the query to return record set order −

mysql> select *from recordSetOrderDemo where EmployeeId IN(100,10,20,50)
-> ORDER BY FIND_IN_SET(EmployeeId,'100,10,20,50');

This will produce the following output −

+------------+--------------+
| EmployeeId | EmployeeName |
+------------+--------------+
| 100        | Mike         |
| 10         | Larry        |
| 10         | David        |
| 20         | John         |
| 50         | Sam          |
+------------+--------------+
5 rows in set (0.03 sec)

Updated on: 30-Jul-2019

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