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Get the name of the file and path in Java
The name of the file and the name of the path can be obtained using the methods java.io.File.getName() and java.io.File.getPath() respectively. The getName() returns the name of the file or the directory. The getPath() returns the abstract pathname in the form of a pathname string.
A program that demonstrates this is given as follows −
Example
import java.io.File;
public class Demo {
public static void main(String[] args) {
File file = new File("C:" + File.separator + "jdk11.0.2" + File.separator, "demo1.java");
System.out.println("File name: " + file.getName());
System.out.println("Path name: " + file.getPath());
}
}The output of the above program is as follows −
Output
File name: demo1.java Path name: C:/jdk11.0.2/demo1.java
Now let us understand the above program.
The file name and path name of the file is printed using the methods getName() and getPath() respectively. A code snippet that demonstrates this is given as follows −
File demo1 = new File("C:" + File.separator + "jdk11.0.2" + File.separator, "demo1.java");
System.out.println("File name: " + demo1.getName());
System.out.println("Path name: " + demo1.getPath());
Updated on: 30-Jul-2019
6K+ Views
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