Get the first element from a Sorted Set in Java

Java 8Object Oriented ProgrammingProgramming

To create a Sorted Set, firstly create a Set.

Set<Integer> s = new HashSet<Integer>();

Add elements to the above set.

int a[] = {77, 23, 4, 66, 99, 112, 45, 56, 39, 89};
Set<Integer> s = new HashSet<Integer>();
try {
   for(int i = 0; i < 5; i++) {
      s.add(a[i]);
    }

After that, use TreeSet class to sort.

TreeSet sorted = new TreeSet<Integer>(s);

Get the first element, using the first() method −

System.out.println("\nFirst element of the sorted set = "+ (Integer)sorted.first());

The following is the code to get the first element from a Sorted Set in Java.

Example

 Live Demo

import java.util.*;
public class Demo {
   public static void main(String args[]) {
      int a[] = {77, 23, 4, 66, 99, 112, 45, 56, 39, 89};
      Set<Integer> s = new HashSet<Integer>();
      try {
         for(int i = 0; i < 5; i++) {
            s.add(a[i]);
         }
         System.out.println(s);
         TreeSet sorted = new TreeSet<Integer>(s);
         System.out.println("Sorted list = ");
         System.out.println(sorted);
         System.out.println("\nFirst element of the sorted set = "+ (Integer)sorted.first());
      } catch(Exception e) {}
   }
}

Output

[66, 99, 4, 23, 77]
Sorted list =
[4, 23, 66, 77, 99]
First element of the sorted set = 4
raja
Published on 30-Jan-2019 10:29:10
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