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Get the first element from a Sorted Set in Java
To create a Sorted Set, firstly create a Set.
Set<Integer> s = new HashSet<Integer>();
Add elements to the above set.
int a[] = {77, 23, 4, 66, 99, 112, 45, 56, 39, 89};
Set<Integer> s = new HashSet<Integer>();
try {
for(int i = 0; i < 5; i++) {
s.add(a[i]);
}After that, use TreeSet class to sort.
TreeSet sorted = new TreeSet<Integer>(s);
Get the first element, using the first() method −
System.out.println("
First element of the sorted set = "+ (Integer)sorted.first());The following is the code to get the first element from a Sorted Set in Java.
Example
import java.util.*;
public class Demo {
public static void main(String args[]) {
int a[] = {77, 23, 4, 66, 99, 112, 45, 56, 39, 89};
Set<Integer> s = new HashSet<Integer>();
try {
for(int i = 0; i < 5; i++) {
s.add(a[i]);
}
System.out.println(s);
TreeSet sorted = new TreeSet<Integer>(s);
System.out.println("Sorted list = ");
System.out.println(sorted);
System.out.println("
First element of the sorted set = "+ (Integer)sorted.first());
} catch(Exception e) {}
}
}Output
[66, 99, 4, 23, 77] Sorted list = [4, 23, 66, 77, 99] First element of the sorted set = 4
Updated on: 30-Jul-2019
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