Get the count of two table fields in a single MySQL query?

For this, you can use the CASE statement along with SUM(). Here, we will be finding the count of Male and Female records from a column with employee gender values. Let us first create a table −

mysql> create table DemoTable
(
   EmployeeGender ENUM('Male','Female')
);
Query OK, 0 rows affected (0.52 sec)

Insert some records in the table using insert command −

mysql> insert into DemoTable values('Male');
Query OK, 1 row affected (0.19 sec)
mysql> insert into DemoTable values('Female');
Query OK, 1 row affected (0.13 sec)
mysql> insert into DemoTable values('Male');
Query OK, 1 row affected (0.10 sec)
mysql> insert into DemoTable values('Female');
Query OK, 1 row affected (0.08 sec)
mysql> insert into DemoTable values('Male');
Query OK, 1 row affected (0.07 sec)
mysql> insert into DemoTable values('Female');
Query OK, 1 row affected (0.08 sec)

Display all records from the table using select statement −

mysql> select *from DemoTable;

This will produce the following output −

+----------------+
| EmployeeGender |
+----------------+
| Male           |
| Female         |
| Male           |
| Female         |
| Male           |
| Female         |
+----------------+
6 rows in set (0.00 sec)

Following is the query to get the count of two table fields in one query −

mysql> select
sum(case when EmployeeGender='Male' then 1 else 0 end) as Total_Number_Of_Male_Employee,
sum(case when EmployeeGender='Female' then 1 else 0 end) as Total_Number_Of_Female_Employee
from DemoTable;

This will produce the following output −

+-------------------------------+---------------------------------+
| Total_Number_Of_Male_Employee | Total_Number_Of_Female_Employee |
+-------------------------------+---------------------------------+
|                             3 |                               3 |
+-------------------------------+---------------------------------+
1 row in set (0.00 sec