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Get super class of an object in Java
The immediate superclass of any entity such as an object, class, primitive type, interface etc. can be obtained using the method java.lang.Class.getSuperclass(). This method contains no parameters.
A program that demonstrates this is given as follows −
Example
public class Main {
public static void main(String[] args) {
Object obj1 = new String("Hello");
Object obj2 = new Integer(15);
Class c1 = obj1.getClass().getSuperclass();
System.out.println("Super Class = " + c1);
Class c2 = obj2.getClass().getSuperclass();
System.out.println("Super Class = " + c2);
}
}Output
Super Class = class java.lang.Object Super Class = class java.lang.Number
Now let us understand the above program.
In the method main(), getClass() is used to obtain the class and getSuperclass() is used to obtain the super class of objects obj1 and obj2. Then the super class is printed. A code snippet which demonstrates this is as follows −
Object obj1 = new String("Hello");
Object obj2 = new Integer(15);
Class c1 = obj1.getClass().getSuperclass();
System.out.println("Super Class = " + c1);
Class c2 = obj2.getClass().getSuperclass();
System.out.println("Super Class = " + c2);
Updated on: 25-Jun-2020
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