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Get substring in MongoDB aggregate
To get substring, use $substr in MongoDB. Let us create a collection with documents −
> db.demo176.insertOne({"ProductName":"PRODUCT-1"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e3843a09e4f06af551997ef")
}
> db.demo176.insertOne({"ProductName":"PRODUCT-102"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e3843a69e4f06af551997f0")
}
> db.demo176.insertOne({"ProductName":"PRODUCT-105"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e3843aa9e4f06af551997f1")
}Display all documents from a collection with the help of find() method −
> db.demo176.find();
This will produce the following output −
{ "_id" : ObjectId("5e3843a09e4f06af551997ef"), "ProductName" : "PRODUCT-1" }
{ "_id" : ObjectId("5e3843a69e4f06af551997f0"), "ProductName" : "PRODUCT-102" }
{ "_id" : ObjectId("5e3843aa9e4f06af551997f1"), "ProductName" : "PRODUCT-105" }Following is the query to get substring in MongoDB aggregate −
> db.demo176.aggregate(
... [
... {
... $project:
... {
...
... ProductName: { $substr: [ "$ProductName", 0, 7] }
...
... }
... }
... ]
...)This will produce the following output −
{ "_id" : ObjectId("5e3843a09e4f06af551997ef"), "ProductName" : "PRODUCT" }
{ "_id" : ObjectId("5e3843a69e4f06af551997f0"), "ProductName" : "PRODUCT" }
{ "_id" : ObjectId("5e3843aa9e4f06af551997f1"), "ProductName" : "PRODUCT" }
Updated on: 27-Mar-2020
457 Views
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