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Get all the interfaces implemented or inherited by the current Type in C#
To get all the interfaces implemented or inherited by the current Type, the code is as follows −
Example
using System; public class Demo { public static void Main() { Type type = typeof(float); Type myInterface = type.GetInterface("IFormattable",true); Type[] myInterfaces = type.GetInterfaces(); Console.WriteLine("Interface = "+myInterface); Console.WriteLine("All the Interfaces..."); for (int i = 0; i < myInterfaces.Length; i++) Console.WriteLine(""+myInterfaces[i]); } }
Output
This will produce the following output −
Interface = System.IFormattable All the Interfaces... System.IComparable System.IFormattable System.IConvertible System.IComparable`1[System.Single] System.IEquatable`1[System.Single]
Let us see another example −
Example
using System; public class Demo { public static void Main() { Type type = typeof(int); Type myInterface = type.GetInterface("IFormattable"); Type[] myInterfaces = type.GetInterfaces(); Console.WriteLine("Interface = "+myInterface); Console.WriteLine("All the Interfaces..."); for (int i = 0; i < myInterfaces.Length; i++) Console.WriteLine(""+myInterfaces[i]); } }
Output
This will produce the following output −
Interface = System.IFormattable All the Interfaces... System.IComparable System.IFormattable System.IConvertible System.IComparable`1[System.Int32] System.IEquatable`1[System.Int32]
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