Get all the interfaces implemented or inherited by the current Type in C#

To get all the interfaces implemented or inherited by the current Type, the code is as follows −

Example

 Live Demo

using System;
public class Demo {
   public static void Main() {
      Type type = typeof(float);
      Type myInterface = type.GetInterface("IFormattable",true);
      Type[] myInterfaces = type.GetInterfaces();
      Console.WriteLine("Interface = "+myInterface);
      Console.WriteLine("All the Interfaces...");
      for (int i = 0; i < myInterfaces.Length; i++)
      Console.WriteLine(""+myInterfaces[i]);
   }
}

Output

This will produce the following output −

Interface = System.IFormattable
All the Interfaces...
System.IComparable
System.IFormattable
System.IConvertible
System.IComparable`1[System.Single]
System.IEquatable`1[System.Single]

Let us see another example −

Example

 Live Demo

using System;
public class Demo {
   public static void Main() {
      Type type = typeof(int);
      Type myInterface = type.GetInterface("IFormattable");
      Type[] myInterfaces = type.GetInterfaces();
      Console.WriteLine("Interface = "+myInterface);
      Console.WriteLine("All the Interfaces...");
      for (int i = 0; i < myInterfaces.Length; i++)
      Console.WriteLine(""+myInterfaces[i]);
   }
}

Output

This will produce the following output −

Interface = System.IFormattable
All the Interfaces...
System.IComparable
System.IFormattable
System.IConvertible
System.IComparable`1[System.Int32]
System.IEquatable`1[System.Int32]

AmitDiwan

Updated on 11-Dec-2019 10:01:43

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