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Get all the interfaces implemented or inherited by the current Type in C#
To get all the interfaces implemented or inherited by the current Type, the code is as follows −
Example
using System;
public class Demo {
public static void Main() {
Type type = typeof(float);
Type myInterface = type.GetInterface("IFormattable",true);
Type[] myInterfaces = type.GetInterfaces();
Console.WriteLine("Interface = "+myInterface);
Console.WriteLine("All the Interfaces...");
for (int i = 0; i < myInterfaces.Length; i++)
Console.WriteLine(""+myInterfaces[i]);
}
}Output
This will produce the following output −
Interface = System.IFormattable All the Interfaces... System.IComparable System.IFormattable System.IConvertible System.IComparable`1[System.Single] System.IEquatable`1[System.Single]
Let us see another example −
Example
using System;
public class Demo {
public static void Main() {
Type type = typeof(int);
Type myInterface = type.GetInterface("IFormattable");
Type[] myInterfaces = type.GetInterfaces();
Console.WriteLine("Interface = "+myInterface);
Console.WriteLine("All the Interfaces...");
for (int i = 0; i < myInterfaces.Length; i++)
Console.WriteLine(""+myInterfaces[i]);
}
}Output
This will produce the following output −
Interface = System.IFormattable All the Interfaces... System.IComparable System.IFormattable System.IConvertible System.IComparable`1[System.Int32] System.IEquatable`1[System.Int32]
Updated on: 11-Dec-2019
300 Views
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