Get a specific interface implemented or inherited by the current Type in C#

To get a specific interface implemented or inherited by the current Type, the code is as follows −

Example

 Live Demo

using System;
public class Demo {
   public static void Main() {
      Type type = typeof(double);
      Type myInterface = type.GetInterface("IFormattable");
      Console.WriteLine("Interface = "+myInterface);
   }
}

Output

This will produce the following output −

Interface = System.IFormattable

Example

Let us see another example −

 Live Demo

using System;
public class Demo {
   public static void Main() {
      Type type = typeof(float);
      Type myInterface = type.GetInterface("IFormattable",true);
      Console.WriteLine("Interface = "+myInterface);
   }
}

Output

This will produce the following output −

Interface = System.IFormattable

AmitDiwan

Updated on: 11-Dec-2019

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