FloatBuffer put() method in Java


The required value can be written at the current position of the buffer and then the current position is incremented using the method put() in the class java.nio.FloatBuffer. This method requires a single parameter i.e. the value to be written in the buffer and it returns the buffer in which the value is inserted.

A program that demonstrates this is given as follows −

Example

 Live Demo

import java.nio.*;
import java.util.*;
public class Demo {
   public static void main(String[] args) {
      int n = 5;
      try {
         FloatBuffer buffer = FloatBuffer.allocate(n);
         buffer.put(4.5F);
         buffer.put(1.2F);
         buffer.put(3.9F);
         buffer.put(7.5F);
         buffer.put(5.8F);
         buffer.rewind();
         System.out.println("The FloatBuffer is: " + Arrays.toString(buffer.array()));
      } catch (BufferOverflowException e) {
         System.out.println("Error!!! BufferOverflowException");
      } catch (ReadOnlyBufferException e) {
         System.out.println("Error!!! ReadOnlyBufferException");
      }
   }
}

The output of the above program is as follows −

Output

The FloatBuffer is: [4.5, 1.2, 3.9, 7.5, 5.8]

karthikeya Boyini
karthikeya Boyini

I love programming (: That's all I know

Updated on: 30-Jul-2019

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