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Finding words in a matrix in JavaScript
We are required to write a JavaScript function that takes in an array of arrays of characters as the first argument and a string as the second argument.
The function should find out whether there exist characters in the matrix, non-repeating combination of which yields the string provided to the function as the second argument.
If there exists such a combination, our function should return true, false otherwise.
For example −
If the input array and the string are −
const arr = [ ['s', 'd', 'k', 'e'], ['j', 'm', 'o', 'w'], ['y', 'n', 'l'] ]; const str = 'don';
Then the output should be −
const output = false;
Example
Following is the code −
const arr = [
['s', 'd', 'k', 'e'],
['j', 'm', 'o', 'width'],
['y', 'n', 'l']
];
const str = 'don';
const containsWord = (arr = [], str = '') => {
if (arr.length === 0){
return false;
};
const height = arr.length;
const width = arr[0].length;
const dirs = [[-1, 0], [0, 1], [1, 0], [0, -1]];
const tryWord = (x, y, k) => {
if (arr[x][y] !== str[k]) return false;
if (k === str.length - 1) return true;
arr[x][y] = '*';
for (const [dx, dy] of dirs) {
const i = x + dx;
const j = y + dy;
if (i >= 0 && i < height && j >= 0 && j < width) {
if (tryWord(i, j, k + 1)) return true;
}
}
arr[x][y] = str[k]; // reset
return false;
};
for (let i = 0; i < height; i++) {
for (let j = 0; j < width; j++) {
if (tryWord(i, j, 0)) return true;
}
}
return false;
};
console.log(containsWord(arr, str));Output
Following is the console output −
false
Updated on: 19-Jan-2021
227 Views
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