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Finding sort order of string in JavaScript
We are required to write a JavaScript function that takes in a string and checks whether it is sorted or not.
For example:
isSorted('adefgjmxz') // true isSorted('zxmfdba') // true isSorted('dsfdsfva') // false
Therefore, let’s write the code for this function −
Example
The code for this will be −
const str = 'abdfhlmxz'; const findDiff = (a, b) => a.charCodeAt(0) - b.charCodeAt(0); const isStringSorted = (str = '') => { if(str.length < 2){ return true; }; let res = '' for(let i = 0; i < str.length-1; i++){ if(findDiff(str[i+1], str[i]) > 0){ res += 'u'; }else if(findDiff(str[i+1], str[i]) < 0){ res += 'd'; }; if(res.indexOf('u') && res.includes('d')){ return false; }; }; return true; }; console.log(isStringSorted(str));
Output
The output in the console will be −
true
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