Finding number of alphabets, digits and special characters in strings using C language

Following is the logic we implement to find alphabets, digits and special characters −

for(number=0;string[number]!='\0';number++) {// for loop until endof string
   if(string[number]>='a'&&string[number]<='z'||string[number]>='A'&&string[number]<='Z') //checking       alphabets in string{
      alphabets=alphabets+1; //counting alphabets
         //alphabets++;
   }
   else if(string[number]>='0'&&string[number]<='9'){ //checking numbers in string
      digits=digits+1; //counting numbers
      //digits++;
   } else {
      special=special+1; //counting special characters
      //special++;
   }
}

Following program is to identify total number of alphabets, digits, and special characters in a string −

Example

 Live Demo

#include<stdio.h>
#include<ctype.h>
void main(){
   //Declaring integer for number determination, string//
   int number;
   char string[50];
   int alphabets=0;
   int digits=0;
   int special=0;
   //Reading User I/p//
   printf("Enter the string :");
   gets(string);
   for(number=0;string[number]!='\0';number++){
      if(string[number]>='a'&&string[number]<='z'||string[number]>='A'&&string[number]<='Z'){
         alphabets=alphabets+1;
         //alphabets++;
      }
      else if(string[number]>='0'&&string[number]<='9'){
         digits=digits+1;
         //digits++;
      }
      else{
         special=special+1;
         //special++;
      }
   }
   //Printing number of alphabets, number of digits, number of special characters//
   printf("The number of alphabets in the string is : %d
",alphabets);
   printf("The number of digits in the string is : %d
",digits);
   printf("The number of special characters in the string is : %d
",special);
}

Output

Enter the string :The number of alphabets in the string is : 0
The number of digits in the string is : 0
The number of special characters in the string is : 1