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Finding next n leap years in JavaScript
We are required to write a function that takes a positive integer n and returns an array of next n leap years. We will break this problem into three parts −
Part 1: Finding current year via JS
The code to find current year via JS will be −
// getting the current year from a new instance of Date object const year = new Date().getFullYear();
Part 2: Checking for leap year
We will now write a function isLeap() that takes in a number and returns a boolean based on the number being a leap year or not.
A year is considered as a leap year if atleast one of these two conditions are met −
- It is multiple of 400.
- It is multiple of 4 and not multiple of 100.
Keeping these things in mind let’s write the function isLeap() −
// function to check for a leap year
const isLeap = year => {
return year % 400 === 0 || (year % 4 === 0 && year % 100 !== 0);
};Part 3: Finding next n leap years
Example
// function to check for a leap year
const isLeap = year => {
return year % 400 === 0 || (year % 4 === 0 && year % 100 !== 0);
};
const nextNLeap = n => {
const arr = [];
let year = new Date().getFullYear()+1;
while(arr.length < n){
if(isLeap(year++)){
arr.push(year-1);
};
};
return arr;
};
console.log(nextNLeap(5));
console.log(nextNLeap(25));Output
The output in the console will be −
[ 2024, 2028, 2032, 2036, 2040 ] [ 2024, 2028, 2032, 2036, 2040, 2044, 2048, 2052, 2056, 2060, 2064, 2068, 2072, 2076, 2080, 2084, 2088, 2092, 2096, 2104, 2108, 2112, 2116, 2120, 2124 ]
Updated on: 28-Aug-2020
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