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Finding a number, when multiplied with input number yields input number in JavaScript
Problem
We are required to write a JavaScript function that takes in a positive integer n written as abcd... (a, b, c, d... being digits) and a positive integer p
- we want to find a positive integer k, if it exists, such as the sum of the digits of n taken to the successive powers of p is equal to k * n.
In other words −
Is there an integer k such as : (a ^ p + b ^ (p+1) + c ^(p+2) + d ^ (p+3) + ...) = n * k
If it is the case, we will return k, if not return -1.
Example
Following is the code −
const num = 695; const p = 2; const findDesiredNumber = (num, p) => { let sum = 0; let str = String(num); for(const char in str){ sum += str[char] * p; p++; }; return Number.isInteger(sum/num) ? sum/num : -1; }; console.log(findDesiredNumber(num, p));
Output
Following is the console output −
-1
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