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Finding a number, when multiplied with input number yields input number in JavaScript
Problem
We are required to write a JavaScript function that takes in a positive integer n written as abcd... (a, b, c, d... being digits) and a positive integer p
- we want to find a positive integer k, if it exists, such as the sum of the digits of n taken to the successive powers of p is equal to k * n.
In other words −
Is there an integer k such as : (a ^ p + b ^ (p+1) + c ^(p+2) + d ^ (p+3) + ...) = n * k
If it is the case, we will return k, if not return -1.
Example
Following is the code −
const num = 695;
const p = 2;
const findDesiredNumber = (num, p) => {
let sum = 0;
let str = String(num);
for(const char in str){
sum += str[char] * p;
p++;
};
return Number.isInteger(sum/num) ? sum/num : -1;
};
console.log(findDesiredNumber(num, p));Output
Following is the console output −
-1
Updated on: 19-Apr-2021
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