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Find unique pairs such that each element is less than or equal to N in C++
In this tutorial, we are going to learn how to find the unique pairs that are less than the given number n.
Let's see the steps to solve the problem.
Initialize the number.
Iterate from i = 1 to i < n.
Iterate from j = i + 1 to j < n.
Print the (i, j).
Example
Let's see the code.
#include <bits/stdc++.h>
using namespace std;
void uniquePairs(int n) {
for (int i = 1; i < n; ++i) {
for (int j = i + 1; j < n; j++) {
cout << "(" << i << "," << j << ")" << endl;
}
}
}
int main() {
int n = 5;
uniquePairs(n);
return 0;
}Output
If you execute the above program, then you will get the following result.
(1,2) (1,3) (1,4) (2,3) (2,4) (3,4)
Conclusion
If you have any queries in the tutorial, mention them in the comment section.
Published on 29-Dec-2020 10:42:55
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