Find the slope of the given number using C++

In this problem, we are given a number N. Our task is to find the slope of the given number.

Slope of a number is the total number of maxima and minima digits in the number.

Maxima digit is the digit whose both neighbours (previous and next) are smaller.

Maxima digit is the digit whose both neighbours (previous and next) are greater.

Let’s take an example to understand the problem,

Input

N = 9594459

Output

2

Solution Approach

A simple solution to the problem is by traversing the number digit by digit from excluding the first and last one (the don’t count form maxima or minima). Now, for each digit, we will check whether the digits are greater or smaller than digits before and after it. At last, we will return the maxima and minima count.

Example

Program to illustrate the working of our solution

#include <iostream>
using namespace std;
int findNumberSlope(string N, int len){
   int slope = 0;
   for (int i = 1; i < len - 1; i++) {
      if (N[i] > N[i - 1] && N[i] > N[i + 1])
         slope++;
      else if (N[i] < N[i - 1] && N[i] < N[i + 1])
         slope++;
   }
   return slope;
}
int main(){
   string N = "574473434329";
   int len = N.size();
   cout<<" The slope of the given number is "<<findNumberSlope(N, len);
   return 0;
}

Output

The slope of the given number is 7