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Find the most frequent number in the array and how many times it is repeated in JavaScript
We are required to write a JavaScript function that takes in an array of literals and finds the most frequent number in the array and how many times it is repeated.
Example
The code for this will be −
const arr = ['13', '4', '1', '1', '4', '2', '3', '4', '4', '1', '2', '4', '9', '3'];
const findFrequency = (arr = []) => {
const count = {};
const max = arr.reduce((acc, val, ind) => {
count[val] = (count[val] || 0) + 1;
if (!ind || count[val] > count[acc[0]]) {
return [val];
};
if (val !== acc[0] && count[val] === count[acc[0]]) {
acc.push(val);
};
return acc;
}, undefined);
return {
max, count
};
}
console.log(findFrequency(arr));Output
And the output in the console will be −
{
max: [ '4' ],
count: { '1': 3, '2': 2, '3': 2, '4': 5, '9': 1, '13': 1 }
}
Updated on: 23-Nov-2020
210 Views
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